-3x^2+3x+158=-10

Solution for -3x^2+3x+158=-10 equation:

-3x^2+3x+158=-10

We move all terms to the left:

-3x^2+3x+158-(-10)=0

We add all the numbers together, and all the variables

-3x^2+3x+168=0

a = -3; b = 3; c = +168;
Δ = b2-4ac
Δ = 32-4·(-3)·168
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-45}{2*-3}=\frac{-48}{-6}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+45}{2*-3}=\frac{42}{-6}
=-7
$